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⭕ Circles

Area of Sector

Sector = (angle/360) × area of circle

Grade 8 · Area of Sector

Easy 20 questions Worksheet #92754 For Area of Sector

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Grade 8 · Area of Sector

Easy · 20 questions · Worksheet #92754 · Area of Sector

Name: ________________________

Date: ______________ Score: ______

  1. fill Sector area: θ = 90°, r = 22. Use π ≈ 3.14. (A = (θ/360)×πr²)
    ______________________________
  2. fill Sector area: θ = 60°, r = 21. Use π ≈ 3.14. (A = (θ/360)×πr²)
    ______________________________
  3. fill Sector area: θ = 30°, r = 44. Use π ≈ 3.14. (A = (θ/360)×πr²)
    ______________________________
  4. fill Sector area: θ = 120°, r = 21. Use π ≈ 3.14. (A = (θ/360)×πr²)
    ______________________________
  5. fill Sector area: θ = 180°, r = 27. Use π ≈ 3.14. (A = (θ/360)×πr²)
    ______________________________
  6. fill Sector area: θ = 60°, r = 8. Use π ≈ 3.14. (A = (θ/360)×πr²)
    ______________________________
  7. fill Sector area: θ = 180°, r = 29. Use π ≈ 3.14. (A = (θ/360)×πr²)
    ______________________________
  8. fill Sector area: θ = 120°, r = 26. Use π ≈ 3.14. (A = (θ/360)×πr²)
    ______________________________
  9. fill Sector area: θ = 45°, r = 35. Use π ≈ 3.14. (A = (θ/360)×πr²)
    ______________________________
  10. fill Sector area: θ = 90°, r = 19. Use π ≈ 3.14. (A = (θ/360)×πr²)
    ______________________________
  11. fill Sector area: θ = 45°, r = 46. Use π ≈ 3.14. (A = (θ/360)×πr²)
    ______________________________
  12. fill Sector area: θ = 180°, r = 24. Use π ≈ 3.14. (A = (θ/360)×πr²)
    ______________________________
  13. fill Sector area: θ = 180°, r = 31. Use π ≈ 3.14. (A = (θ/360)×πr²)
    ______________________________
  14. fill Sector area: θ = 120°, r = 14. Use π ≈ 3.14. (A = (θ/360)×πr²)
    ______________________________
  15. fill Sector area: θ = 60°, r = 27. Use π ≈ 3.14. (A = (θ/360)×πr²)
    ______________________________
  16. fill Sector area: θ = 90°, r = 16. Use π ≈ 3.14. (A = (θ/360)×πr²)
    ______________________________
  17. fill Sector area: θ = 30°, r = 45. Use π ≈ 3.14. (A = (θ/360)×πr²)
    ______________________________
  18. fill Sector area: θ = 30°, r = 38. Use π ≈ 3.14. (A = (θ/360)×πr²)
    ______________________________
  19. fill Sector area: θ = 180°, r = 14. Use π ≈ 3.14. (A = (θ/360)×πr²)
    ______________________________
  20. fill Sector area: θ = 120°, r = 13. Use π ≈ 3.14. (A = (θ/360)×πr²)
    ______________________________

Updated July 2026

FAQs

What is Area of Sector?

Area of Sector (sector area) is a circles relationship written as Sector = (angle/360) × area of circle or A = (θ/360) × πr². Students use it to solve unknowns when enough values are known.

How do you calculate Area of Sector step by step?

Write Sector = (angle/360) × area of circle, substitute the known numbers carefully, then simplify. Worked walkthrough: θ = 90° r = 7 A ≈ (90/360)×153.94 ≈ 38.48.

When is Area of Sector taught in school?

Area of Sector usually appears in circles units during middle or secondary school. Match difficulty with MathDigits grade worksheets so practice fits the curriculum year.

What is a real example of Area of Sector?

On this page the worked result is ≈ 38.48. Generate a formula worksheet below for more unique practice sets.

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